There are 90 2-digit numbers
a) 32 are greater than 68, so prob = 32/90
b) 10 are multiples of 9, so ...
c) all are less than 100, so ...
d) 18 have at least one 5, so ...
a two figure number is written down at random find the probability
a)that the number is greater than 68
b)the number is a multiple of 9
c) it is less than 100
d) it contains at least one 5 (i.e a number such as 15 or 55
5 answers
There are 90 two-digit numbers (10-99).
a) 31/90 = ?
b) 18, 27, 36, 45, 54, 63, 72, 81, 90, 99 are multiples of 9.
c) All two-digit numbers are less than 100.
d) 15, 25, 35, 45, 50, 51, 52, 53, 54, 55, 56, 57, 58, 59, 65, 75, 85, 95 all have at least one 5.
a) 31/90 = ?
b) 18, 27, 36, 45, 54, 63, 72, 81, 90, 99 are multiples of 9.
c) All two-digit numbers are less than 100.
d) 15, 25, 35, 45, 50, 51, 52, 53, 54, 55, 56, 57, 58, 59, 65, 75, 85, 95 all have at least one 5.
My bad on (a). PsyDAG is correct
thanks PsyDAG and Steve
6r
1 answer