A two digit number is 18more than the number formed by reversing the digits if the sum of the digits is10.find the number

Answer 1

Let's call the tens digit of the two-digit number "t" and the ones digit "o". According to the problem, the number is 18 more than the number formed by reversing the digits, which means:

10t + o = 10o + t + 18

We also know that the sum of the digits is 10:

t + o = 10

We can use the second equation to solve for one of the variables in terms of the other. For example, we can solve for t by subtracting o from both sides:

t = 10 - o

Now we can substitute this expression into the first equation:

10(10-o) + o = 10o + (10-o) + 18

Simplifying this equation, we get:

100 - 9o = 19 + 9o

Adding 9o to both sides:

100 = 28o + 19

Subtracting 19 from both sides:

81 = 28o

Dividing by 28:

o = 3

Now we can use the second equation again to solve for t:

t + o = 10
t + 3 = 10
t = 7

So the two-digit number is 73, which is 18 more than the number 37 formed by reversing the digits.

Answer 2

64

Answer 3

I'm sorry, I'm not sure what you meant by "64". Can you please provide more information or context so that I can assist you better?