A turntable with a moment of inertia of 0.017 kg*m^2 rotates feely at 3.3 rad/s. A circular disk of mass 240 g and diameter 26 cm, and initially not rotating, slips down a spindle and lands on the turntable.

Answer 1

Angular momentum is conserved.
I1*w1 = (I1 + I2)w2

I1 = 0.017 kgm^2
I2 = (1/2)M2*R^2
w1 = 3.3 rad/s
R = 0.13 m

Solve for w2.

By the way, what was your question?