Asked by Gemma
A turbo-jet flies 50 mph faster than a super-prop plane. If a turbo-jet goes 2000 miles in 3 hours less time than it takes the super-prop to go 2800 miles, find the speed of each plane.
I do not understand how to do this at all. Please explain as well as you can! Thanks.
I do not understand how to do this at all. Please explain as well as you can! Thanks.
Answers
Answered by
bobpursley
LEt v be the velocity of the turbo plane, then v-50 is the velocity of the slower. Let t be the time for turbo to go 2000 miles, then t+3 is the time for super .
(velocity*time)= distance
(v-50)(t+3)=2800
and
v*t=2000
From the second equation, t=2000/v, put that into the first equation.
(v-50)(2000/v + 3)=2800
multiply both sides by v
(v-50)(2000+3v)=2800v
multiply it all out, gather terms, and use the quadratic equation.
(velocity*time)= distance
(v-50)(t+3)=2800
and
v*t=2000
From the second equation, t=2000/v, put that into the first equation.
(v-50)(2000/v + 3)=2800
multiply both sides by v
(v-50)(2000+3v)=2800v
multiply it all out, gather terms, and use the quadratic equation.
Answered by
Michelle
turbo-jet: 400mph
super-prop: 350mph
super-prop: 350mph
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.