t = 2h-4
h = 6
so
t = 12-4 = 8 legs
A true crab has 4 fewer than twice the number of legs that a hermit crab has. The hermit crab has 6 legs. How many legs does the true crab have?
I put for the equation
4c =6 *2
I am confused
3 answers
Thanks for breaking it down.
T =68