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A true crab has 4 fewer than twice the number of legs that a hermit crab has. The hermit crab has 6 legs. How many legs does the true crab have?

I put for the equation

4c =6 *2
I am confused

3 answers

t = 2h-4

h = 6
so
t = 12-4 = 8 legs

Thanks for breaking it down.

T =68

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