A truck covers 40.0 m in 9.40 s while smoothly slowing down to final speed 2.35 m/s. Find its accelerations

Answer 1

average velocity is __ 40.0 m / 9.40 s
or __ 4.26

Answer 2

average velocity is __ 40.0 m / 9.40 s

average equals initial plus final, divided by two

40.0 / 9.40 = (i + 2.35) / 2 __ i = 6.16

acceleration equals final minus initial, divided by time

a = (2.35 - 6.160 / 9.40

Answer 3

a) –4.50 m/s2

b) 4.06 m/s2

c) –4.06 m/s2

d) 4.50 m/s2