A truck accelerating at 0.0083 meters/second2 covers a distance of 5.8 × 104 meters. If the truck's mass is 7,000 kilograms, what is the work done to reach this distance?

Answer 1

F = m*a = 7000kg * 9.8N/kg = 68,600 N.

W = F*d

Answer 2

3369800

Answer 3

WRONG