To find the frequency of the note in Hz, we can use the formula:
f = v / 2L
where:
f = frequency of the note
v = speed of sound in air (approximately 343 m/s at room temperature)
L = length of the tube (3 m)
Plugging in the values, we get:
f = 343 / (2 * 3)
f = 343 / 6
f = 57.17 Hz
Therefore, the frequency of the note played by the trombone player at the end zone of the football field is approximately 57.17 Hz.
A trombone player stands at the end zone (x=0) of a football field and begins to play its fundamental tone. Assume the trombone is a half open tube that is 3 m long.
what is the frequency of the note in Hz
1 answer