A trombone player stands at the end zone (x=0) of a football field and begins to play its fundamental tone. Assume the trombone is a half open tube that is 3 m long. What is the frequency of the note in Hz?

Answer 1

To find the frequency of the fundamental tone produced by the trombone, we can use the formula:

f = v / 2L

where:
f = frequency
v = speed of sound in air (approximately 343 m/s at 20 degrees Celsius)
L = length of the tube (3 m in this case)

Plugging in the values:

f = 343 / (2*3)
f = 343 / 6
f = 57.17 Hz

Therefore, the frequency of the note produced by the trombone is approximately 57.17 Hz.