A triangular region is bound by the three lines 2x+y-12=0, y=3x-3, and y=1/7x-81/7. What is the circumcentre of this triangle?
I can find the answer using a graph, but I don't know the formula to find the mid segments of the lines.
3 answers
PLEASE HELP!!! I can't use a graph for this question and I don't know the formula.
What you'll need to do is
1. find the 3 intersections of the lines, which are then the vertices, (xa,ya), (xb,yb), (xc,yc).
2. Find the mid-points of each side using
Mab=((xa+xb)/2, (ya+yb)/2),
...
3. Find the perpendicular bisector of each side by passing a line perpendicular to the side, and passing through the mid point.
4. The Circumcentre is the intersection of any two of these perpendicular bisectors.
For a numerical example, see:
http://www.algebra.com/algebra/homework/Length-and-distance.faq.question.524163.html
1. find the 3 intersections of the lines, which are then the vertices, (xa,ya), (xb,yb), (xc,yc).
2. Find the mid-points of each side using
Mab=((xa+xb)/2, (ya+yb)/2),
...
3. Find the perpendicular bisector of each side by passing a line perpendicular to the side, and passing through the mid point.
4. The Circumcentre is the intersection of any two of these perpendicular bisectors.
For a numerical example, see:
http://www.algebra.com/algebra/homework/Length-and-distance.faq.question.524163.html
Thank you so much
1 answer