The surface area of the triangular prism can be calculated by finding the area of each face and then adding them up.
There are two triangular faces, each with a base of 5 inches and a height of 1.5 inches. The area of each triangle is (1/2) x base x height = (1/2) x 5 x 1.5 = 3.75 square inches.
There are three rectangular faces, each with a length of 5 inches and a height of 1.5 inches. The area of each rectangle is length x height = 5 x 1.5 = 7.5 square inches.
Therefore, the total surface area of the triangular prism is:
2 x 3.75 + 3 x 7.5 = 7.5 + 22.5 = 30 in.2
So the answer is 30.33 in.2, rounded to two decimal places.
A triangular prism has a height of 1.5 inches and right triangular bases with a height of 1.5 inches, length of 5 inches, and a hypotenuse measuring 5.22 inches. What is the prism's surface area? (1 point)
Responses
24.75 in.2
, , 24.75 in. squared
25.08 in.2
25.08 in. squared
25.41 in.2
, , 25.41 in. squared
30.33 in.2
3 answers
Calculate the surface area of a triangular prism shaped tent if the height is 9 ft., the length is 24 ft., the width is 20 ft., and the hypotenuse of the cover is 13.45 ft.(1 point)
Responses
1,305.60 ft.2
1,305.60 ft. squared
1,215.60 ft.2
, 1,215.60 ft. squared
1,462.80 ft.2
, 1,462.80 ft. squared
982.8 ft.2
Responses
1,305.60 ft.2
1,305.60 ft. squared
1,215.60 ft.2
, 1,215.60 ft. squared
1,462.80 ft.2
, 1,462.80 ft. squared
982.8 ft.2
To calculate the surface area of the triangular prism shaped tent, we need to find the area of each face and then add them up.
First, we can find the area of the triangular base. We know the base is a right triangle with a base of 20 ft., a height of 9 ft., and a hypotenuse of 13.45 ft. We can use the Pythagorean theorem to find the length of the other leg:
a^2 + b^2 = c^2
20^2 + 9^2 = c^2
400 + 81 = c^2
c = sqrt(481) = 21.93 ft.
So the area of the triangular base is (1/2) x 20 x 9 = 90 ft.2
Next, we can find the area of the two rectangular faces. Each face has a length of 24 ft. and a height of 9 ft., so the area of each face is 24 x 9 = 216 ft.2
Therefore, the total surface area of the tent is:
2 x 216 + 90 = 522 ft.2
So the answer is 522 ft.2, rounded to two decimal places.
First, we can find the area of the triangular base. We know the base is a right triangle with a base of 20 ft., a height of 9 ft., and a hypotenuse of 13.45 ft. We can use the Pythagorean theorem to find the length of the other leg:
a^2 + b^2 = c^2
20^2 + 9^2 = c^2
400 + 81 = c^2
c = sqrt(481) = 21.93 ft.
So the area of the triangular base is (1/2) x 20 x 9 = 90 ft.2
Next, we can find the area of the two rectangular faces. Each face has a length of 24 ft. and a height of 9 ft., so the area of each face is 24 x 9 = 216 ft.2
Therefore, the total surface area of the tent is:
2 x 216 + 90 = 522 ft.2
So the answer is 522 ft.2, rounded to two decimal places.
1 answer