A triangular lot sits at the corner of two streets that intersect at an angle of 63 degrees. One street side of the lot is 35m and the other is 47m. how long is the back of the lot, to the nearest metre?

Answer 1

Straight cosine law question

solve

x^2 = 35^2 + 47^2 - 2(35)(47)cos 63

Answer 2

thank you very much.