We can find the equation of a straight line if we know the slope and a point on it, so each part of your question must be reduced to that requirement.
Median: a line from a vertex to the midpoint of the opposite side
So we need the midpoint of LP, which is ( (-3+1)/2 , (6-8)/2 ) = (-1,-1)
Using that point and the point N(3,2) we can find the slope
slope of median = (-1-2)/((-1-3) = 3/4
I now have the slope and a point, so we can find the equation.
Whatever method you learned:
y-2 = (3/4)(x-3)
4y-8 = 3x - 9
3x - 4y = 1
right bisector of AP
you need the midpoint of AP, that's your usable point of the equation
find the slope of AP
the right-bisector's slope would be the reciprocal of the slope of AP
using those hints .....
altitude from N
so you use point N as your point.
the altitude must meet the line AP at right angles, so it is perpendicular.
So ....
Let me know what the other two equations are after you found them.
A triangle is formed from the points L(-3, 6), N(3, 2) and P(1, -8). Find the equation of the following lines.
Find:
the median from N
the right bisector of LP
the altitude from N
1 answer
1 answer