A triangle is drawn on a coordinate plane. Dilate the figure with a magnitude of 3 in reference to the origin. What are the coordinates of the new vertices of A′B′C′

?

(1 point)
Responses

A′(1,−2)
, B′(3,6)
, and C′(9,0)
upper A prime left parenthesis 1 comma negative 2 right parenthesis , upper B prime left parenthesis 3 comma 6 right parenthesis , and upper C prime left parenthesis 9 comma 0 right parenthesis

A′(−23,−53)
, B′(0,1)
, and C′(2,−1)
upper A prime left parenthesis negative Start Fraction 2 over 3 End Fraction comma negative Start Fraction 5 over 3 End Fraction right parenthesis , upper B prime left parenthesis 0 comma 1 right parenthesis , and upper C prime left parenthesis 2 comma negative 1 right parenthesis

A′(−5,−8)
, B′(−3,0)
, and C′(3,0)
upper A prime left parenthesis negative 5 comma negative 8 right parenthesis , upper B prime left parenthesis negative 3 comma 0 right parenthesis , and upper C prime left parenthesis 3 comma 0 right parenthesis

A′(−6,−15)
, B′(0,9)
, and C′(18,−9)

1 answer

To dilate a figure with a magnitude of \( k \) in reference to the origin, you multiply each coordinate of the vertices by \( k \).

Given the dilation magnitude of \( 3 \), if a triangle has original vertices \( A(x_1, y_1) \), \( B(x_2, y_2) \), and \( C(x_3, y_3) \), then the new vertices after dilation will be:

\[ A' = (3x_1, 3y_1) \] \[ B' = (3x_2, 3y_2) \] \[ C' = (3x_3, 3y_3) \]

It's important to know the original coordinates of the triangle's vertices to find the new coordinates after dilation. Since the original coordinates of the triangle are not provided in your message, I can't directly calculate the new coordinates.

However, based on the given options, you can verify which set of coordinates forms valid \( A', B', C' \) vertices when the original coordinates are multiplied by \( 3 \).

If you provide the original coordinates, I can perform the multiplication and help identify the correct responses from the options provided.