A triangle has vertices on a coordinate grid at J (-7,-7),k(-7,3),and L(-1,3). What is the length, in units, of JK

Answer 1

To find the length of side JK in the triangle with vertices at J (-7, -7), K (-7, 3), and L (-1, 3), we can use the distance formula for two points in a coordinate plane, which is:

$$d=\sqrt{(x_2-x_1{)}^2+(y_2-y_1{)}^2}$$

where $(x_1,y_1)$ and $(x_2,y_2)$ are the coordinates of the two points.

However, because both points J and K have the same x-coordinate (both are -7), this means that the line joining these two points is vertical. Therefore, we can simply calculate the distance by subtracting the y-coordinates:

$$JK=|y_2-y_1|$$

So, plugging in the coordinates of J and K:

$$JK=|3-(-7)|$$
$$JK=|3+7|$$
$$JK=|10|$$
$$JK=10$$

Therefore, the length of segment JK is 10 units.