To find the perimeter of a triangle, we need to calculate the distance between each pair of vertices and sum them up.
The distance between two points (x1, y1) and (x2, y2) can be found using the distance formula:
d = √((x2 - x1)^2 + (y2 - y1)^2)
Using this formula, we can calculate the distances between the vertices of the triangle:
d1 = √((-4 - 3)^2 + (-6 - 3)^2) = √(49 + 81) = √130 ≈ 11.40
d2 = √((3 - 7)^2 + (3 - 2)^2) = √16 + 1 = √17 ≈ 4.12
d3 = √((-4 - 7)^2 + (-6 - 2)^2) = √(121 + 64) = √185 ≈ 13.60
Now, we can sum up the distances:
Perimeter = d1 + d2 + d3 = 11.40 + 4.12 + 13.60 = 29.12
Therefore, the closest approximation of the perimeter of the triangle is 29.12, which corresponds to the first option.
A triangle has vertices at (−4,−6), (3,3), (7,2)
Rounded to two decimal places, which of the following is the closest approximation of the perimeter of the triangle?(1 point)
Responses
29.12
29.12
12.36
12.36
15.52
15.52
19.34
1 answer