A triangle has vertices a(0,2),b(3,7)and c(0,6)give that abcd is parallelogram find the area of parallelogram abcd

1 answer

we could use CA as the base of the triangle ABC
then CA = 4
we could use the distance of B(3,7) from the y-axis as the height
height = 3

area of triangle = (1/2)(4)(3) = 6 units^2

so the area of the parallelogram is 12 units^2