A triangle has side lengths of 6, 6, and 9 units. A similar but larger triangle has side lengths of 12, 12, and 18 units. Calculate and compare the perimeters of the two triangles. What is the ratio of the perimeter of the smaller triangle to the perimeter of the larger triangle? Enter your response as a fraction. (1 point)

1 answer

To find the perimeters of the triangles, we need to sum the lengths of their sides.

Smaller Triangle:

  • Side lengths: 6, 6, and 9 units.
  • Perimeter = 6 + 6 + 9 = 21 units.

Larger Triangle:

  • Side lengths: 12, 12, and 18 units.
  • Perimeter = 12 + 12 + 18 = 42 units.

Now, we compute the ratio of the perimeter of the smaller triangle to the perimeter of the larger triangle:

\[ \text{Ratio} = \frac{\text{Perimeter of smaller triangle}}{\text{Perimeter of larger triangle}} = \frac{21}{42} = \frac{1}{2}. \]

Thus, the ratio of the perimeter of the smaller triangle to the perimeter of the larger triangle is:

\[ \boxed{\frac{1}{2}}. \]