The area of a triangle is given by the formula A = (1/2)bh, where b is the base and h is the height.
In this case, we are given that the area is 240 m2 and the base is 2x+1. We need to solve for x.
240 = (1/2)(2x+1)(6x-3)
Multiplying both sides by 2 to eliminate the denominator:
480 = (2x+1)(6x-3)
Distributing on the right side:
480 = 12x^2 - 6x + 6x - 3
Combining like terms:
480 = 12x^2 - 3
Rearranging to isolate the quadratic term:
12x^2 = 480 +3
12x^2 = 483
Dividing both sides by 12:
x^2 = 483/12
x^2 = 40.25
To get x, we take the square root of both sides:
x = √(40.25)
x ≈ 6.34 (rounded to hundredth)
Therefore, the value of x that would give an area of 240 m2 is approximately 6.34.
A triangle has base 2x+1 and height 6x-3. What value of x would give an area of 240 m2? Round to the nearest hundredth.
1 answer