A triangle has a base of 8 cm and a height of 3 cm. The triangle is dilated buy a scale factor of 3. Calculate and compare the areas of dilated triangle and the original triangle.

1 answer

To find the areas of the original triangle and the dilated triangle, we can use the formula for the area of a triangle:

\[ \text{Area} = \frac{1}{2} \times \text{base} \times \text{height} \]

Step 1: Calculate the area of the original triangle

Given:

  • Base = 8 cm
  • Height = 3 cm

Calculating the area:

\[ \text{Area}_{\text{original}} = \frac{1}{2} \times 8 \times 3 = \frac{24}{2} = 12 , \text{cm}^2 \]

Step 2: Find the dimensions of the dilated triangle

The scale factor of dilation is 3. This means that both the base and height of the triangle will be multiplied by 3.

  • New base = \( 8 , \text{cm} \times 3 = 24 , \text{cm} \)
  • New height = \( 3 , \text{cm} \times 3 = 9 , \text{cm} \)

Step 3: Calculate the area of the dilated triangle

Using the new dimensions:

\[ \text{Area}_{\text{dilated}} = \frac{1}{2} \times 24 \times 9 \]

Calculating the area:

\[ \text{Area}_{\text{dilated}} = \frac{1}{2} \times 216 = 108 , \text{cm}^2 \]

Step 4: Compare areas of the dilated triangle and the original triangle

Now we can summarize the areas:

  • Area of the original triangle = \( 12 , \text{cm}^2 \)
  • Area of the dilated triangle = \( 108 , \text{cm}^2 \)

Ratio of the Areas

The ratio of the area of the dilated triangle to the original triangle is given by the square of the scale factor, which is:

\[ \text{Scale factor} = 3 \]

\[ \text{Area ratio} = \text{Scale factor}^2 = 3^2 = 9 \]

This means the area of the dilated triangle is 9 times larger than that of the original triangle, confirming that:

\[ \text{Area}{\text{dilated}} = 9 \times \text{Area}{\text{original}} = 9 \times 12 , \text{cm}^2 = 108 , \text{cm}^2 \]

Conclusion

  • Area of the original triangle: \( 12 , \text{cm}^2 \)
  • Area of the dilated triangle: \( 108 , \text{cm}^2 \)
  • The area of the dilated triangle is 9 times the area of the original triangle.