A triangle as a perimeter of 53 cm. The shortest side of the triangle is 2 cm more than 1/3 of the longest side and the other side is 5 cm less than the longer side. Find the dimensions.

Answer 1

let the longest side be x
shortest side = (1/3)x + 2
other side = x-5

x + (1/3)x + 2 + x - 5 = 53
times 3
3x + x + 6 + 3x - 15 = 159
7x = 168
x = 24

longest side = 24
shortest = 10
other = 19

check: 24+10+19 = 53

Answer 2

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