A transverse wave is formed on a long skipping rope. The equation of the transverse wave is y=5.50 sin(0.031π x+5.52π t) where x and y are in centimeters, t is in seconds, and Π is pi (3.14..). Find the amplitude of the wave? what is the wavelength of the transverse wave? Find the frequency of the wave?calculate the speed of the wave?calculate the transverse displacement when x=3.9cm and t=0.29s?

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7 years ago

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Scroll down some here, and all is explained.

http://www.insula.com.au/physics/1279/L14.html

answered by Steve

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A transverse wave is formed on a long skipping rope. The equation of the transverse wave is y=5.50 sin(0.031π x+5.52π t) where x and y are in centimeters, t is in seconds, and Π is pi (3.14..). Find the amplitude of the wave? what is the wavelength of the transverse wave? Find the frequency of the wave?calculate the speed of the wave?calculate the transverse displacement when x=3.9cm and t=0.29s?

1 answer

Scroll down some here, and all is explained.

http://www.insula.com.au/physics/1279/L14.html

Ask a New Question or answer this question.

Steve · Answer

Scroll down some here, and all is explained. http://www.insula.com.au/physics/1279/L14.html