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A translation is a slide of the figure to a new location on the coordinate plane.

Now, find the coordinates of the vertices of the image of triangle 𝐼𝐽𝐾 after the translation 3 units to the left.



(1 point)
Responses

I' (1,0), J' (-1,-4), K' (-5,4)
I' (1,0), J' (-1,-4), K' (-5,4)

I' (1,0), J' (1,4), K' (5,4)
I' (1,0), J' (1,4), K' (5,4)

I' (0,1), J' (-4,-1), K' (4,-5)
I' (0,1), J' (-4,-1), K' (4,-5)

I' (7,0), J' (5,-4), K' (1,4)
I' (7,0), J' (5,-4), K' (1,4)
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there is a triangle shap around k j i

1 answer

To find the coordinates of the vertices of triangle \( IJK \) after a translation 3 units to the left, you will subtract 3 from the x-coordinate of each vertex.

Let's denote the original coordinates of the vertices of triangle \( IJK \) as:

  • \( I(x_1, y_1) \)
  • \( J(x_2, y_2) \)
  • \( K(x_3, y_3) \)

After translating 3 units to the left, the new coordinates of the vertices will be:

  • \( I'(x_1 - 3, y_1) \)
  • \( J'(x_2 - 3, y_2) \)
  • \( K'(x_3 - 3, y_3) \)

Now, let's check the provided responses based on this rule:

  1. I' (1,0), J' (-1,-4), K' (-5,4)
  2. I' (1,0), J' (1,4), K' (5,4)
  3. I' (0,1), J' (-4,-1), K' (4,-5)
  4. I' (7,0), J' (5,-4), K' (1,4)

Unfortunately, you did not provide the original coordinates of vertices \( I, J, \) and \( K \). Therefore, I cannot definitively determine which response is correct.

If you provide the original coordinates of the vertices, I can calculate the new coordinates after the translation and verify the appropriate response among the options provided.