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A translation is a slide of the figure to a new location on the coordinate plane.

Now, find the coordinates of the vertices of the image of triangle 𝐼𝐽𝐾 after the translation 3 units to the left.



(1 point)
Responses

I' (1,0), J' (-1,-4), K' (-5,4)
I' (1,0), J' (-1,-4), K' (-5,4)

I' (1,0), J' (1,4), K' (5,4)
I' (1,0), J' (1,4), K' (5,4)

I' (0,1), J' (-4,-1), K' (4,-5)
I' (0,1), J' (-4,-1), K' (4,-5)

I' (7,0), J' (5,-4), K' (1,4)
I' (7,0), J' (5,-4), K' (1,4)
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1 answer

To perform a translation of a triangle (or any figure) 3 units to the left, you need to subtract 3 from the x-coordinates of each vertex of the triangle.

However, you haven't provided the original coordinates of the vertices \( I \), \( J \), and \( K \). If you provide those coordinates, I can help you find the new coordinates after the translation.

Let’s say the original coordinates were:

  • \( I(x_1, y_1) \)
  • \( J(x_2, y_2) \)
  • \( K(x_3, y_3) \)

After translating 3 units to the left, the new coordinates would be:

  • \( I'(x_1 - 3, y_1) \)
  • \( J'(x_2 - 3, y_2) \)
  • \( K'(x_3 - 3, y_3) \)

Please provide the original coordinates for a specific solution.