To find the image of (2,3) under the transformation with the rule (x,y)->(2x+3, y+4), we can simply plug in the values of x=2 and y=3 into the rule.
(2,3) -> (2(2) + 3, 3 + 4)
= (4 + 3, 7)
= (7, 7)
Therefore, the image of (2,3) under this transformation is (7,7).
A transformation has the rule (x,y)->(2x+3,y+4). Find the image of (2,3) under this transformation
1 answer