Asked by Mota
A trajectile, of mass 20 g, traveling at 350 m/s, strikes a steel plate at an angle of 30-degrees with a plane of the plate. It ricochets off at the same angle, at a speed of 320 m/s. What is the magnitude of the impulse that the steel plate gives to the trajectile?
Answers
Answered by
bobpursley
Find the velocity components perpendicular to the plate, and parallel to the plate.
initial: perpendicular speed=350sin30
parallel speed=350cos30
final: perpendicular:320sin30
parallel: 320 sin30
find the change of momentum for each direction.
perpendicularspeed change: sin30(350+320)=670sin30
parallel speed change: cos30(350-320)
30cos30
and momentum changes in those directions are that speed change multiplied by mass.
resultant velocity change:
velocitychange=sqrt(perpend^2 + parall^2)
= sqrt ((30cos30)^2 + (670sin30)^2)
calculate that out, multiply it by mass m.
That is the change of momentum, and it is the same as impluls.
initial: perpendicular speed=350sin30
parallel speed=350cos30
final: perpendicular:320sin30
parallel: 320 sin30
find the change of momentum for each direction.
perpendicularspeed change: sin30(350+320)=670sin30
parallel speed change: cos30(350-320)
30cos30
and momentum changes in those directions are that speed change multiplied by mass.
resultant velocity change:
velocitychange=sqrt(perpend^2 + parall^2)
= sqrt ((30cos30)^2 + (670sin30)^2)
calculate that out, multiply it by mass m.
That is the change of momentum, and it is the same as impluls.
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