a train starts from rest and accelerates unifotmly, until it has travled 3.7 km and acquired a velocity of 30 m/s. the train then moves at a constant velocity of 30 m/s for 410 s. the train then slows down uniformly at 0.065 m/s^2, until it reaches a halt. what distance does the train travel while it is slowing down

2 answers

All that stuff at the beginning is irrelevant here. When the train starts to slow down,
v=30m/s
a = -.065 m/s^2

So, it takes 30/.065 = 461.5 seconds to stop

s = 30t - .0325t^2 = 6923m = 6.9 km
. A train starts from rest and accelerates uniformly, until it has traveled 3.7 km and acquired a velocity of The train then moves at a constant velocity of for 410 s. The train then slows down uniformly at until it reaches a halt. What distance does the train travel while it is slowing down?