Asked by mattie
A train slows down as it rounds a sharp horizontal turn, slowing from 87.4 km/h to 44.6 km/h in the 16.1 s that it takes to round the bend. The radius of the curve is 180 m. Compute the acceleration at the moment the train speed reaches 44.6 km/h. Assume that it continues to slow down at this time at the same rate. what or how do i find the magnitude and dierction?
Answers
Answered by
bobpursley
magnitude acceleration=(87.4-44.6)/16.1 is the tangential acceleration, in the direction it is going.
Now there is another acceleartion, directed at the center of the circle, centripetal acceleration, 44.1^2/180
These two accelerations are at 90 degrees to each other.
Magnitude= sqrt(tangential magnitude^2+centripetal^2)
direction, theta=arctan centriptal/tangential where theta is the angle measured from the tangent towards the radius.
Now there is another acceleartion, directed at the center of the circle, centripetal acceleration, 44.1^2/180
These two accelerations are at 90 degrees to each other.
Magnitude= sqrt(tangential magnitude^2+centripetal^2)
direction, theta=arctan centriptal/tangential where theta is the angle measured from the tangent towards the radius.
Answered by
anon
Where to get 44.1 for Velocity as in the Centripetal Acceleration?
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.