Since the velocity of the train is constant at 54kmph, the average velocity is 54kmph.
Proof:
D1 = 54(.5) = 27km.
D1 = 54(.6666666) = 36
Vav = (27 + 36)/1.16666 = 54kmph.
a train moving at constant velocity of 54 k mph moves east wards for 30 min, then due to north with the same speed for 40 min. What is the average velocity of the train during the run?(in k mph)
4 answers
D1 = 54• 0.5 = 27km.
D1 = 54• 0.67 = 36 km.
Displacement d =sqrt(D1² + D2)²) = sqrt (27² +36²) =45 km.
Total time is 30+40 =70 min =1.17 hr
Average velocity =displacement/tame taken =>
Average velocity V(ave) = d/t = 45/1.17 =38.57 km/hr.
Note!
Average speed = distance travelled/ time taken =>
Average speed v(ave)= (27+36)/1.17 =53.85 km/hr
D1 = 54• 0.67 = 36 km.
Displacement d =sqrt(D1² + D2)²) = sqrt (27² +36²) =45 km.
Total time is 30+40 =70 min =1.17 hr
Average velocity =displacement/tame taken =>
Average velocity V(ave) = d/t = 45/1.17 =38.57 km/hr.
Note!
Average speed = distance travelled/ time taken =>
Average speed v(ave)= (27+36)/1.17 =53.85 km/hr
Last line is
Average speed v(ave)= (27+36)/1.17 =54 km/hr
Average speed v(ave)= (27+36)/1.17 =54 km/hr
38.4km/hr
2 answers