A train leaves port Harcourt to Mano at 40km/h 2 hours later before another train leaves kano for port Harcourt at 60km/h. if the two towns are 1470km apart and the trains maintain these speed, how soon will they meet

Answer 1

v = s / t

s = v ∙ t

Speed of first train:

v1 = 40 km / h

Speed of second train:

v2 = 60 km / h

After 2 hours the first train is away from the port port Harcourt:

40 km / h ∙ 2 h = 80 km

When the second train starts travel the distance between the trains is:

1470 - 80 = 1390 km

The distance the first train will travel is:

s1 = v1 ∙ t

s1 = 40 t

The distance the second train will travel is:

s2 = v2 ∙ t

s2 = 60 t

When trains meet the sum of these two distances must be 1390 km.

s1 + s2 = 40 t + 60 t = 100 t = 1390

100 t = 1390

t = 1390 / 100

t = 13.9 h

Since one hour has 60 minutes:

t = 13 h + 0.9 ∙ 60 min

t = 13 h 54 min