speed of slower train --- x mph
speed of faster train ---- x + 28 mph
distance covered by slower train = 5x
distance covered by faster train = 3(x+28) , (from 3:00pm to 6:00pm is 3 hrs)
but they covered the same distance, so
5x = 3(x+28)
solve for x to get speed of slower train
A train leaves New York at 1:00 PM. A second train leaves the same city in the same direction at 3:00 PM. The second train travels 28 mph faster than the first. If the second train overtakes the first at 6:00 PM, what is the speed of each of the two trains?
1 answer