Here S=44m
V=42m/s
U=?
a=3m/s²
Now we know that
2as=v²-u²
2(3)(44)=(42)²-u²
u=10√15m/s
A train is moving parallel and adjacent to a
highway with a constant speed of 30 m/s. Ini-
tially a car is 44 m behind the train, traveling
in the same direction as the train at 42 m/s
and accelerating at 3 m/s2.
What is the speed of the car just as it passes
the train?
3 answers
38.73
Thanks you