it's probably easiest to find out how long it takes, then recall that v = at.
So, if we have the car start the race at t=0, x=0,
35t + 3/2 t^2 = 48+24t
t = 3.07
so, v = 3*3.07 = 9.21 m/s
A train is moving parallel and adjacent to a
highway with a constant speed of 24 m/s. Initially a car is 48 m behind the train, traveling
in the same direction as the train at 35 m/s
and accelerating at 3 m/s ^2 .
What is the speed of the car just as it passes
the train?
1 answer
1 answer