Le A be the angle of inclination (4 degrees).
T = string tension force.
Write the vertical and horizontal Newton's second law equations
W = M g = T cos A
M a = T sin A
Eliminate T
a/g = tan A = 0.0699
Solve for a
A train is moving along a straight horizontal track. A pendulum suspended from the roof of one of the carriages of train is inclined at four degree to the vertical. Calculate tge acceleration of train
2 answers
mg=TcosA
ma=TsinA
a/g=sinA/cosA
a/g=tanA
=0.0699
a=g*0.0699=9.81*0.0699= 0.6857m/s^2
ma=TsinA
a/g=sinA/cosA
a/g=tanA
=0.0699
a=g*0.0699=9.81*0.0699= 0.6857m/s^2
2 answers