A train is going at 1/3 of its usual speed and it takes an extra 30 minutes to reach its destination. Find its usual time to cover the same distance.

Answer 1

Not enough information:
e.g. suppose the distance is 90 km
and the usual speed is x km/h
then 90/(x/3) - 90/x = 1/2
(270-90)/x = 1/2 ----> x = 360 km/h

but suppose the distance is 60 km
then 60/(x/3) - 60/x = 1/2
(180-60)/x = 1/2 ---> x = 240 km/h

So the speed depends on the distance, and we are not given that

Answer 2

I wasn't given the distance, but isn't there any way to solve it?

Answer 3

pop

Answer 4

so the formula is time = distance / speed

Answer 5

im sorry i checked again

its not letting me type anym

Answer 6

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