Asked by Hannah Montana

A train going 60 mph left several minutes before the 63mph train. Traveling on parallel tracks the faster train reaches the slower one in 3 hours. How many minutes head start did the slower train have?
Answered by Henry
Both trains had traveled the same distance:

d1 = d2.

60t = 63*3 = 189 mi.
t = 3.15h.

3.15h - 3h = 0.15h = 9min head start.
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