A traffic light hangs from a pole as shown. The uniform aluminum pole AB is 7.70m long and has a mass of 11.0kg. The mass of the traffic light is 27.5m.

Question

1. Determine the tension in the horizontal massless cable CD.
2. Determine the vertical and horizontal components of the force exerted by the pivot A on the aluminum pole.

Answer 1

I'm not sure how to post a picture with it but some more additional information that I did not add.
The two poles and cable make a right triangle where CA is the shortest side at 3.80m, CD (the cable), and AD as the hypotenuse. CDA is an angle of 37 degrees.

Answer 2

I believe that t mass of the traffic light is 27.5 kg!!!
We choose the coordinate system with positive torques clockwise.
The sum of torques ΣM= 0 about the point A
ΣM =-T•H+M•g•L•cosθ+m•g•(L/2)•cos θ = 0;
-T(3.80 )+ 27.5•9.80•7.7•cos37° + 11• 9.8•(7.7/2)cos37° = 0,
Solve for T
The sum of forces ΣF = 0
ΣFx = F(H) - T= 0;
F(H) =…
ΣFy = F(V) - Mg -mg = 0;
F(V)=…