A traditional number cube is rolled twice. What is the probability that the first roll lands on an even number, and the second roll lands on an odd number? Express your answer as a simplified fraction.

Answer 1

Since a traditional number cube has 6 sides with numbers 1-6, there are 3 even numbers (2, 4, 6) and 3 odd numbers (1, 3, 5).

The probability of the first roll landing on an even number is 3/6 or 1/2.

Once the first roll has landed on an even number, there are still 6 possible outcomes for the second roll, 3 of which are odd numbers. So, the probability of the second roll landing on an odd number given that the first roll was even is 3/6 or 1/2.

Therefore, the probability that the first roll lands on an even number, and the second roll lands on an odd number is (1/2) * (1/2) = 1/4 or 25%.