To solve this problem, we need to consider the forces acting on the rock. The forces acting on the rock are:
1. Force of gravity (weight) acting downwards
2. Force of the tractor pulling to the right
3. Force of friction acting to the left
4. Normal force of the ground acting upwards
First, we will calculate the force of gravity on the rock:
Weight = mass x acceleration due to gravity
Weight = 150 kg x 9.8 m/s^2
Weight = 1470 N
Next, we will calculate the net force acting on the rock in the horizontal direction:
Net force = force of the tractor - force of friction
Net force = 1200 N - 750 N
Net force = 450 N
Since the rock is accelerating horizontally (due to an unbalanced force acting on it), we can use Newton's second law to calculate the normal force of the ground on the rock. The normal force is the force that balances the force of gravity in the vertical direction:
Net force = mass x acceleration
450 N = 150 kg x a
a = 3 m/s^2
Now, we can calculate the normal force:
Normal force = weight - mass x acceleration
Normal force = 1470 N - 150 kg x 3 m/s^2
Normal force = 1470 N - 450 N
Normal force = 1020 N
Therefore, the force of gravity on the rock is 1470 N, and the normal force of the ground on the rock is 1020 N.
A tractor pulls a 150 kg rock to the right with a force of 1200 N against a force of friction of 750 N [left].
• Calculate the force of gravity on the rock and the normal force of the ground on the rock.
1 answer