To calculate the force of gravity on the rock, we can use the formula Fg = m*g, where m is the mass of the rock and g is the acceleration due to gravity (9.8 m/s^2).
Fg = 150 kg * 9.8 m/s^2 = 1470 N
To calculate the normal force of the ground on the rock, we can use the formula FN = Fg, since the rock is not accelerating in the vertical direction.
FN = 1470 N
Now, let's draw a free body diagram of the rock:
Fg (1470 N) Fn (1470 N)
↑ ↑
ϕ ----------------→
friction (750 N) | force (1200 N)
The net force acting on the rock can be calculated by summing up all the forces in the horizontal direction:
Fnet = 1200 N - 750 N = 450 N to the right
Now, using Newton's second law (F = m*a), we can find the acceleration of the rock:
450 N = 150 kg * a
a = 3 m/s^2
Therefore, the acceleration of the rock is 3 m/s^2.
A tractor pulls a 150 kg rock to the right with a force of 1200 N against a force of friction of 750 N [left].
• Calculate the force of gravity on the rock and the normal force of the ground on the rock.
• Draw a FBD of the rock, and determine the magnitude and direction of the net force acting on the rock.
• Use Newton’s second law to find the acceleration of the rock.
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