A toy rocket engine is securely fastened to a large puck that can glide with negligible friction over a horizontal surface, taken as the xy plane. The 5.60-kg puck has a velocity of 1.40î m/s at one instant. Eight seconds later, its velocity is (6.00î + 4.0ĵ) m/s.

Question

(a) Assuming the rocket engine exerts a constant horizontal force, find the components of the force.
(___î + ___ĵ)N

(b) Find its magnitude.
___N

Answer 1

In the x direction
change in x speed = 6-1.4 = 4.6 m/s
Newton #2 is Force = rate of change of momentum
so Fx = 5.60 kg * 4.6 m/s / 8s = 3.22 Newtons
and
Fy = 5.60 * (4-0)/8 = 2.8 N
F = Fx i + Fy j

magnitude = sqrt (Fx^2+Fy^2)

Answer 2

thank you so much, that really helped!

Answer 3

wow thanks