A toy race car zooms across the ground with an acceleration of 1.8 m/s^2. After 3 seconds it has a final velocity of 12.2 m/s, what is the toy car's initial velocity? a= (Vf-Vi)/t (1 point) Responses 22.8 m/s 22.8 m/s 6.8 m/s 6.8 m/s 9.8 m/s 9.8 m/s 1.8 m/s

Answer 1

To find the toy car's initial velocity (Vi), you can use the formula for acceleration:

\[ a = \frac{Vf - Vi}{t} \]

In this case, you've been given:

• \( a = 1.8 , \text{m/s}^2 \)
• \( Vf = 12.2 , \text{m/s} \)
• \( t = 3 , \text{s} \)

Rearranging the formula to solve for \( Vi \):

\[ Vi = Vf - a \cdot t \]

Now plug in the values:

\[ Vi = 12.2 , \text{m/s} - (1.8 , \text{m/s}^2 \cdot 3 , \text{s}) \]

Calculating the term \( 1.8 \cdot 3 \):

\[ 1.8 \cdot 3 = 5.4 , \text{m/s} \]

Now substitute it back into the equation:

\[ Vi = 12.2 , \text{m/s} - 5.4 , \text{m/s} \]

Calculating \( Vi \):

\[ Vi = 6.8 , \text{m/s} \]

So the toy car's initial velocity is 6.8 m/s.