To find the initial velocity (Vi), we can rearrange the equation a = (Vf - Vi)/t to solve for Vi.
a = acceleration = 1.8 m/s^2
Vf = final velocity = 12.2 m/s
t = time = 3 s
Rearranging the equation:
a = (Vf - Vi)/t
a * t = Vf - Vi
Vi = Vf - a * t
Now we can substitute the values:
Vi = 12.2 m/s - 1.8 m/s^2 * 3 s
Calculating the equation:
Vi = 12.2 m/s - 5.4 m/s
Vi = 6.8 m/s
Therefore, the toy car's initial velocity is 6.8 m/s.
A toy race car zooms across the ground with an acceleration of 1.8 m/s^2. After 3 seconds it has a final velocity of 12.2 m/s, what is the toy car's initial velocity? a= (Vf-Vi)/t
3 answers
A car accelerates from 5 m/s to 15 m/s in 2 s. What is its acceleration? a= (Vf-Vi)/t
To find the acceleration (a), we can use the formula a = (Vf - Vi)/t.
Vf = final velocity = 15 m/s
Vi = initial velocity = 5 m/s
t = time = 2 s
Substituting the given values into the equation:
a = (15 m/s - 5 m/s) / 2 s
Calculating the equation:
a = 10 m/s / 2 s
a = 5 m/s^2
Therefore, the car's acceleration is 5 m/s^2.
Vf = final velocity = 15 m/s
Vi = initial velocity = 5 m/s
t = time = 2 s
Substituting the given values into the equation:
a = (15 m/s - 5 m/s) / 2 s
Calculating the equation:
a = 10 m/s / 2 s
a = 5 m/s^2
Therefore, the car's acceleration is 5 m/s^2.
1 answer