To analyze the forces acting on the toy helicopter, we need to consider both the forward (horizontal) and upward (vertical) forces separately.
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Force Forward:
- The helicopter is flying forward with a force of 15 N.
- There is an oncoming wind that opposes this force with 10 N.
- The net forward force is therefore: \(15\ \text{N forward} - 10\ \text{N wind} = 5\ \text{N forward}\).
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Force Upward:
- The helicopter has an upward force from its propeller of 10 N.
- The force of gravity pulling it down is 5 N.
- The net upward force is: \(10\ \text{N upward} - 5\ \text{N downward} = 5\ \text{N upward}\).
Based on this analysis, the toy helicopter is flying forward with a net force of 5 N and upward with a net force of 5 N.
Therefore, the correct response is: The toy helicopter is flying forward with a force of 5 N and upward with a force of 5 N.