a toy cannon fires a projectile from ground level with a speed of 15.0 m/s, at an angle of 30.0 degrees above the horizontal.

a) calculate the horizontal range of projectile.

R=Vi^2/g * sin 2theta
= (150/9.8)*(sin(2*30.0)
= 19.88m
I know this part is right but i'm not sure what to do next?

b) calculate the maximum height for the trajectory.

c) calculate the components of the projectile's impact velocity.

1 answer

R=vₒ²•sin2α/g,

h= vₒ²•sin²α/2g,

t= 2vₒ•sinα/g

v(x) =v₀(x)= v₀•cos α
v(y) =-v₀(y) = - v₀•sin α