The balloon had 1.00g He initially and a radius of 10.0 cm. Calculate the volume of the sphere (V = (4/3)*pi*r^3) and convert 1.00 g He to mols. Use PV = nRT and solve for P (no T is given so assume a convenient number--then use that in all other calculations).
Then 0.25 g He is removed which leaves 0.75g. Convert to mols, use PV = nRT and solve for the new V (use P from the first calculation and T you assumed). Convert V to the new radius. Don't forget that V in PV = nRT is in L but if you use cm for the radius and (4/3)*pi*r^, that V is in cc.
A toy balloon originally held 1.00 g of helium gas and had a radius of 10.0 cm.
During the night, 0.25 g of the gas effused from the balloon. Assuming ideal
gas behavior under these constant pressure and temperature conditions, what
was the radius of the balloon the next morning?
3 answers
9.08cm
We need the solution not the explanation
1 answer