To find the length of the sidewalk, we need to find the perimeter of the park.
The perimeter of a rectangle is calculated by adding the lengths of all its sides.
For this park, the length is 65 yards and the width is 40 yards.
So, the perimeter of the park is 2*(length + width) = 2*(65 + 40) = 2*(105) = 210 yards.
Therefore, the length of the sidewalk across the park is 210 yards.
None of the given options are equal to 210 yards, so there seems to be an error in the provided responses.
A town wants to put a sidewalk across a popular park. They have measured the dimensions of the park to use in calculating the length of the proposed sidewalk. Find the sidewalk length to the nearest tenth of a yard. The dimensions of the park are 65 yards and 40 yards.
Responses
A. 76.3 yards
B. 105 yards
C. 81 yards
D. 69.5 yards
5 answers
There isn't an error. Can you try to solve this a different way that fits the provided responses?
Apologies for the confusion. Let's try to solve this using a different approach.
To find the length of the sidewalk, we need to find the diagonal of the park, as it will be the shortest path across the park.
Using the Pythagorean theorem, we can calculate the diagonal:
Diagonal^2 = Length^2 + Width^2
Diagonal^2 = 65^2 + 40^2
Diagonal^2 = 4225 + 1600
Diagonal^2 = 5825
Diagonal = √5825
Diagonal ≈ 76.3 yards (rounded to the nearest tenth)
Therefore, the length of the proposed sidewalk across the park is approximately 76.3 yards.
Option A, 76.3 yards, is the closest match among the given options.
To find the length of the sidewalk, we need to find the diagonal of the park, as it will be the shortest path across the park.
Using the Pythagorean theorem, we can calculate the diagonal:
Diagonal^2 = Length^2 + Width^2
Diagonal^2 = 65^2 + 40^2
Diagonal^2 = 4225 + 1600
Diagonal^2 = 5825
Diagonal = √5825
Diagonal ≈ 76.3 yards (rounded to the nearest tenth)
Therefore, the length of the proposed sidewalk across the park is approximately 76.3 yards.
Option A, 76.3 yards, is the closest match among the given options.
Its aright, and thank you!!! I appreciate it very much.
You're welcome! I'm glad I was able to help. If you have any more questions, feel free to ask.