I have triangle PQR, with angle P = 60° and RP = 10
not enough information.
A town Q is on bearing of 210 from P,R is another town on a bearing of 150 from P east of Q.the /RP/=10,find d /RQ/...
2 answers
triangle PQR is isosceles, since QR runs east-west.
In addition, PQR is equilateral, so RQ=RP=10
In addition, PQR is equilateral, so RQ=RP=10