L=37 m
v₁=5.95 m/s
v₂=7.8 m/s
L+ v₁t= v₂t
t=L/ (v₂-v₁)=
=37/(7.8-5.95) =20 s
d= v₁t=5.95•20=119 m.
A tourist being chased by an angry bear is running in a straight line toward his car at a speed of 5.95 m/s. The car is a distance d away. The bear is 37.0 m behind the tourist and running at 7.80 m/s. The tourist reaches the car safely. What is the maximum possible value for d?
1 answer