A total of $8000 is deposited into two simple interest accounts. On one account, the annual interest rate is 10%, while on the second account the annual simple interest rate is 12%. How much should be invested in the 10% account so that the total annual interest earned is $900?

Answer 1

.10x + .12(8000-x) = 900

Answer 2

my answer 3000

Answer 3

mine, too

Answer 4

An investment club invested a part of $14,000 in a 9% annual simple interest account and the remainder in a 15% annual simple interest account. The amount of interest earned for one year was $1800. How much was invested in the 9% account?

my answer =2400

Answer 5

.09x + .15(14000-x) = 1800

better check your work